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Next: Differential Equations Up: Calculus/Integration Previous: Calculus/Integration

Multidimensional Integrals

1.
One dimensional integrals of functions of two (or more) dimensions are known as ``line integrals''. One has, given f(x,y),

\begin{displaymath}\int_{path} f(x,y) ds
\end{displaymath}

where ds is the differential element of distance along the specified path
2.
Two dimensional integrals of functions of two dimensions are related to areas.

\begin{displaymath}\int_a^b dx \left (
\int_c^d dy f(x,y)
\right )
\end{displaymath}

If f(x,y) were 1, then this would give the rectangular area bounded by $a\leq x \leq b$ and $c \leq y \leq d$.
3.
Three dimensional integrals of functions of 3 dimensions are related to volumes.

\begin{displaymath}\int_a^b dx \left (
\int_c^d dy \left (
\int_e^f dz g(x,y,z)
\right )
\right )
\end{displaymath}

If g(x,y,z) were 1, then this would give the rectangular volume bounded by $a\leq x \leq b$ and $c \leq y \leq d$ and $e \leq y \leq f$.
4.
In two dimensions, one often can use polar coordinates instead of cartesian, i.e., $(r , \theta)$ rather than (x,y). The differential area element changes from dxdy to $rdrd\theta$.

\begin{displaymath}x = r \cos \theta \end{displaymath}

and

\begin{displaymath}y = r \sin \theta\end{displaymath}

, with $0 \le r \le \infty$ and $0 \le \theta \le 2 \pi$.
5.
In 3 dimensions, one often can use spherical polar coordinates instead of cartesian, i.e., $(r, \theta, \phi)$ rather than (x,y,z). The differential volume element changes from dxdydz to $r^2dr \sin \theta d
\theta d\phi$.

\begin{displaymath}x = r \sin \theta \cos \phi\end{displaymath}


\begin{displaymath}y = r \sin \theta \sin \phi\end{displaymath}


\begin{displaymath}x = r \cos \theta \end{displaymath}

with $0 \le r \le \infty$, $0 \le \theta \le \pi$ and $0 \le \phi \le 2
\pi$.


next up previous
Next: Differential Equations Up: Calculus/Integration Previous: Calculus/Integration

2002-06-14