Energetics of the Bohr Atom (II).
If n changes from one value to another, there is an associated change in energy
(?E) =- RH(1/n2-1/m2) but this is equal to the energy of the photon, h? .
Example, if n=1 and m=2, then 2.18x10- 18 (1/12-1/22) = 6.626x10-34 ? , solve for ?! The only trick is the sign, since it is irrelevant (de facto absolute value). Sign indicates difference between emission and absorption.