ch5q8

Calculate the mass (in grams) of Helium in a rigid balloon which can lift a person of "mass" 194.5 pounds (453.6 g/lb). The (fixed) volume of the balloon is 11600 meter³ at 20.22 °C and the outside pressure (of the atmosphere) is 1.98 atm. Take the molecular mass of air to be 28.8 grams/"mole", i.e., (1/5)*32 + (4/5)*28.
Since the balloon is rigid, the pressure of the Helium inside the balloon does not have to equal the pressure of the outside air. This problem requires you to make the density of the balloon ("mass" + Helium) equal to the ambient density of air (outside the balloon).

Choose your answer in scientific notation, e.g., ±1.000x10^±00
. x 10^{^}

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The last time this file was changed (edited) was Friday, July 21, 20123

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