Taylor-Maclaurin Series

Given an analytic function p(V), one can expand that function about a point V=A, i.e.,

$$\begin{eqnarray*}p(V) = p(A)\, ;\, value \, at \, A\\ + \frac{d p(V)}{dV}(V-A)\... ...cdots\\ + \frac{1}{n!} \frac{d^np(V)}{dV^n} (V-A)^n\\ + \cdots \end{eqnarray*}$$