(Castellan, 3rd Ed).
A mixture of oxygen and hydrogen is analyzed by passing it over hot
copper oxide and through a drying tube.
Hydrogen reduces the CuO according to the reaction
CuO(s) + H2(g) -> Cu(s) + H2O(g) (rxn 1)
Oxygen then reoxidizes the copper formed:
Cu(s) + ½ O2(g) -> CuO(s) (rxn 2)
100.0 cm^3 of the mixture measured at 25° C and 750 Torr yields 84.5
cm^3 of dry oxygen measured at the same temperature and pressure after passage
over CuO and the drying agent.
What is the mole fraction of oxygen in the original mixture?
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Numerical value for mole fraction of O_2 in original mixture. Query, is the above answer correct?